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Question
`sin^2 theta + cos^4 theta = cos^2 theta + sin^4 theta`
Solution
LHS = `sin^2 theta + cos ^4 theta`
=`sin^2 theta + ( cos ^2 theta )^2`
=`sin^2 theta + (1- sin^2 theta)^2`
=` sin^2 theta + 1 -2 sin^2 theta + sin ^4 theta`
=`1-sin^2 theta + sin^4 theta`
=`cos^2 theta + sin^4 theta`
= RHS
Hence, LHS = RHS
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