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The Number of Solutions of the Equation Tan − 1 2 X + Tan − 1 3 X = π 4 is (A) 2 (B) 3 (C) 1 (D) None of These - Mathematics

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Question

The number of solutions of the equation \[\tan^{- 1} 2x + \tan^{- 1} 3x = \frac{\pi}{4}\] is

 

Options

  • 2

  • 3

  • 1

  • none of these

MCQ
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Solution

(a) 2
We know that
\[\tan^{- 1} x + \tan^{- 1} y = \tan^{- 1} \left( \frac{x + y}{1 - xy} \right)\]
\[\therefore \tan^{- 1} 2x + \tan^{- 1} 3x = \frac{\pi}{4}\]
\[ \Rightarrow \tan^{- 1} \left( \frac{2x + 3x}{1 - 2x \times 3x} \right) = \frac{\pi}{4}\]
\[ \Rightarrow \frac{2x + 3x}{1 - 2x \times 3x} = \tan\frac{\pi}{4}\]
\[ \Rightarrow \frac{5x}{1 - 6 x^2} = 1 \]
\[ \Rightarrow 5x = 1 - 6 x^2 \]
\[ \Rightarrow 6 x^2 + 5x - 1 = 0\]

Therefore, there are two solutions.

 
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Chapter 4: Inverse Trigonometric Functions - Exercise 4.16 [Page 120]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 8 | Page 120

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