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प्रश्न
Evaluate the following : `int_0^a 1/(a^2 + ax - x^2)*dx`
उत्तर
Let I = `int_0^a 1/(a^2 + ax - x^2)*dx`
a2 + ax – x2 = `a^2 - (x^2 - ax + a^2/4) + a^2/(4)`
= `(5a^2)/(4) - (x - a/2)^2`
= `(sqrt(5a)/2)^2 - (x - a/2)^2`
∴ I = `int_0^a dx/(((sqrt(5)a)/2)^2 - (x - a/2)^2)`
= `(1)/((2 xx sqrt(5)a)/2)*[log|((sqrt(5)a)/2 + x - a/2)/((sqrt(5)a)/(2) - x + a/2)|]_0^a`
= `(1)/(sqrt(5)a)[log|((sqrt(5)a)/2 + a - a/2)/((sqrt(5)a)/(2) - a + a/2)| - log |((sqrt(5)a)/2 - a/2)/((sqrt(5)a)/(2) + a/2)|]`
= `(1)/(sqrt(5)a)[log |(sqrt(5)/2 + 1/2)/(sqrt(5)/2 - 1/2)| - log |(sqrt(5)/2 - 1/2)/(sqrt(5)/2 + 1/2)|]`
= `(1)/(sqrt(5)a)[log|((sqrt(5) + 1)/(sqrt(5) - 1))|- log|((sqrt(5) - 1)/(sqrt(5) + 1))|]`
= `(1)/(sqrt(5)a) log|(sqrt(5) + 1)/(sqrt(5) - 1) xx (sqrt(5) + 1)/(sqrt(5) - 1)|`
= `(1)/(sqrt(5)a) log [((sqrt(5) + 1)/(sqrt(5) - 1))^2]`
= `(1)/(sqrt(5)a) log |(5 + 1 + 2sqrt(5))/(5 + 1 - 2sqrt(5))|`
= `(1)/(sqrt(5)a) log (6 + 2sqrt(5))/(6 - 2sqrt(5))`
= `(1)/(sqrt(5)a) log|(6 + 2sqrt(5))/(6 - 2sqrt(5)) xx (6 + 2sqrt(5))/(6 + 2sqrt(5))|`
= `(1)/(sqrt(5)a) log|(36 + 20 + 24sqrt(5))/(36 - 20)|`
= `(1)/(sqrt(5)a) log |(56 + 24sqrt(5))/(16)|`
= `(1)/(sqrt(5)a) log|(7 + 3sqrt(5))/(2)|`.
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