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प्रश्न
`sin^-1(sin (7pi)/6)`
उत्तर
We know
`sin(sin^-1theta)=theta if - pi/2<=theta<=pi/2`
We have
`sin^-1(sin (7pi)/6)=sin^-1{sin(pi+pi/6)}`
`=sin^-1(sin-pi/6)`
`=-pi/6`
APPEARS IN
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