Advertisements
Advertisements
प्रश्न
Evaluate :
उत्तर
\[\int\left( \frac{e^{6 \log x} - e^{5 \ log x}}{e^{4 \ log x} - e^{3 \ log x}} \right)dx\]
`=∫( ( e^(log x^ 6) - e^(log x^5 ))/(e^(log x^4 )-e^(log x^3)))dx`
\[ = \int\left( \frac{x^6 - x^5}{x^4 - x^3} \right)dx\]
\[ = \int\frac{x^5}{x^3}dx\]
\[ = \int x^2 dx\]
\[ = \frac{x^3}{3} + C\]
APPEARS IN
संबंधित प्रश्न
Evaluate: `int1/(xlogxlog(logx))dx`
Evaluate : `int_0^4(|x|+|x-2|+|x-4|)dx`
Evaluate : `int1/(3+5cosx)dx`
Evaluate `int_(-1)^2|x^3-x|dx`
find `∫_2^4 x/(x^2 + 1)dx`
Evaluate :
`∫_0^π(4x sin x)/(1+cos^2 x) dx`
Evaluate the integral by using substitution.
`int_0^1 x/(x^2 +1)`dx
Evaluate the integral by using substitution.
`int_0^(pi/2) sqrt(sin phi) cos^5 phidphi`
Evaluate the integral by using substitution.
`int_0^1 sin^(-1) ((2x)/(1+ x^2)) dx`
Evaluate the integral by using substitution.
`int_0^2 dx/(x + 4 - x^2)`
Evaluate `int_0^(pi/4) (sinx + cosx)/(16 + 9sin2x) dx`
Evaluate of the following integral:
Evaluate of the following integral:
Evaluate of the following integral:
Evaluate:
Evaluate the following definite integral:
Evaluate the following integral:
\[\int\limits_0^2 \left| x^2 - 3x + 2 \right| dx\]
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate : \[\int\limits_{- 2}^1 \left| x^3 - x \right|dx\] .
Evaluate: `int_ e^x ((2+sin2x))/cos^2 x dx`
Evaluate: `int_-π^π (1 - "x"^2) sin "x" cos^2 "x" d"x"`.
`int_(pi/5)^((3pi)/10) [(tan x)/(tan x + cot x)]`dx = ?
If `I_n = int_0^(pi/4) tan^n theta "d"theta " then " I_8 + I_6` equals ______.
`int_0^1 sin^-1 ((2x)/(1 + x^2))"d"x` = ______.
Evaluate:
`int (1 + cosx)/(sin^2x)dx`
If `int x^5 cos (x^6)"d"x = "k" sin (x^6) + "C"`, find the value of k.