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प्रश्न
If y = cos−1 [sin (4x)], find `("d"y)/("d"x)`
उत्तर
y = cos−1 [sin (4x)]
= `cos^-1 [cos(pi/2 - 4^x)]`
= y = `pi/2 - 4^x`
Differentiating w.r.t. x, we get
`("d"y)/("d"x) = "d"/("d"x)(pi/2 - 4^x)`
= 0 – 4x log 4
= – 4x log 4
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