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Evaluate : 3 sin 3 B + 2 cos ( 2 B + 5 ° ) 2 cos 3 B – sin ( 2 B – 10 ° ) ; when "B" = 20° - Mathematics

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Question

Evaluate : 

`(3 sin 3"B" + 2 cos(2"B" + 5°))/(2 cos 3"B" – sin (2"B" – 10°)` ; when "B" = 20°.

Sum

Solution

Given that B = 20°

`(3 sin 3"B"+2 cos(2"B"+5°))/(2 cos 3"B" – sin (2"B" – 10°)` = `(3 sin 3 xx 20°+2 cos(2 xx 20°+5°))/(2 cos 3 xx 20° – sin (2 xx 20° – 10°))`

= `( 3 sin 60° + 2 cos 45°)/(2 cos 60° – sin 30°)`

= `(3(sqrt3/2) + 2(1/sqrt2))/(2(1/2) – (1)/(2)`

= `(3(sqrt3)/(2) + sqrt2)/(2)`

= `3 sqrt3  + 2 sqrt2`

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Chapter 23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios] - Exercise 23 (A) [Page 292]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (A) | Q 11.2 | Page 292

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