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Question
Evaluate the following:
`sec^-1{sec (-(7pi)/3)}`
Solution
We know that
sec-1 (sec θ) = θ, [0, π/2) ∪ (π/2, π]
We have
`sec^-1{sec (-(7pi)/3)}=sec^-1{sec((7pi)/3)}`
`=sec^-1[sec(2pi+pi/3)]`
`=sec^-1[sec(pi/3)]`
`=pi/3`
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