English

Find the General Solution for Each of the Following Equations Sec2 2x = 1– Tan 2x - Mathematics

Advertisements
Advertisements

Question

Find the general solution for each of the following equations sec2 2x = 1– tan 2x

Solution

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Trigonometric Functions - Exercise 3.4 [Page 78]

APPEARS IN

NCERT Mathematics [English] Class 11
Chapter 3 Trigonometric Functions
Exercise 3.4 | Q 8 | Page 78

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Find the principal and general solutions of the equation `tan x = sqrt3`


If \[\tan x = \frac{a}{b},\] show that

\[\frac{a \sin x - b \cos x}{a \sin x + b \cos x} = \frac{a^2 - b^2}{a^2 + b^2}\]

Prove that:

\[\sin\frac{8\pi}{3}\cos\frac{23\pi}{6} + \cos\frac{13\pi}{3}\sin\frac{35\pi}{6} = \frac{1}{2}\]

 


Prove that

\[\frac{\sin(180^\circ + x) \cos(90^\circ + x) \tan(270^\circ - x) \cot(360^\circ - x)}{\sin(360^\circ - x) \cos(360^\circ + x) cosec( - x) \sin(270^\circ + x)} = 1\]

 


In a ∆ABC, prove that:

\[\tan\frac{A + B}{2} = \cot\frac{C}{2}\]

Find x from the following equations:
\[x \cot\left( \frac{\pi}{2} + \theta \right) + \tan\left( \frac{\pi}{2} + \theta \right)\sin \theta + cosec\left( \frac{\pi}{2} + \theta \right) = 0\]


If tan \[x = - \frac{1}{\sqrt{5}}\] and θ lies in the IV quadrant, then the value of cos x is

 

If \[cosec x - \cot x = \frac{1}{2}, 0 < x < \frac{\pi}{2},\]

 

If sec x + tan x = k, cos x =


The value of \[\tan1^\circ \tan2^\circ \tan3^\circ . . . \tan89^\circ\] is

 

Find the general solution of the following equation:

\[\tan 3x = \cot x\]

Find the general solution of the following equation:

\[\sin x = \tan x\]

Solve the following equation:
\[\sin^2 x - \cos x = \frac{1}{4}\]


Solve the following equation:

\[4 \sin^2 x - 8 \cos x + 1 = 0\]

Solve the following equation:

\[\cos x + \sin x = \cos 2x + \sin 2x\]

Solve the following equation:

\[\tan x + \tan 2x + \tan 3x = 0\]

Solve the following equation:

\[\tan 3x + \tan x = 2\tan 2x\]

Solve the following equation:
\[\sin x + \cos x = \sqrt{2}\]


Solve the following equation:
\[\cot x + \tan x = 2\]

 


If secx cos5x + 1 = 0, where \[0 < x \leq \frac{\pi}{2}\], find the value of x.


Write the number of solutions of the equation
\[4 \sin x - 3 \cos x = 7\]


Write the values of x in [0, π] for which \[\sin 2x, \frac{1}{2}\]

 and cos 2x are in A.P.


If \[\cos x + \sqrt{3} \sin x = 2,\text{ then }x =\]

 


If \[\tan px - \tan qx = 0\], then the values of θ form a series in

 


The general solution of the equation \[7 \cos^2 x + 3 \sin^2 x = 4\] is


If \[\cot x - \tan x = \sec x\], then, x is equal to

 


If \[\sqrt{3} \cos x + \sin x = \sqrt{2}\] , then general value of x is


Find the principal solution and general solution of the following:
cot θ = `sqrt(3)`


Solve the following equations:
sin 5x − sin x = cos 3


Choose the correct alternative:
If f(θ) = |sin θ| + |cos θ| , θ ∈ R, then f(θ) is in the interval


Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π.


Solve `sqrt(3)` cos θ + sin θ = `sqrt(2)`


If sin θ and cos θ are the roots of the equation ax2 – bx + c = 0, then a, b and c satisfy the relation ______.


Find the general solution of the equation sinx – 3sin2x + sin3x = cosx – 3cos2x + cos3x


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×