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Find the sum to indicated number of terms in the geometric progressions 1, – a, a2, – a3, ... n terms (if a ≠ – 1). - Mathematics

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Question

Find the sum to indicated number of terms in the geometric progressions 1, – a, a2, – a3, ... n terms (if a ≠ – 1).

Sum

Solution

geometric progressions 1, –a, a2, –a3,…

First term, a = 1, common ratio, r = `(-"a")/1 = -"a"`

∴ Sum of n terms = `("a"(1 - "r"^"n"))/(1 - "r")`, r > 1

= `("a"(-a)^"n")/(1 - "r")`, r > 1

= `(1.[1 - (-"a")^"n"])/(1 -(-"a"))`

= `([1 - (-a)^"n"])/(1 + "a")`

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Chapter 9: Sequences and Series - Exercise 9.3 [Page 192]

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NCERT Mathematics [English] Class 11
Chapter 9 Sequences and Series
Exercise 9.3 | Q 9 | Page 192

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