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If X < 0, Y < 0 Such that Xy = 1, Then Tan−1 X + Tan−1 Y Equals (A) π 2 (B) − π 2 (C) − π (D) None of These - Mathematics

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Question

If x < 0, y < 0 such that xy = 1, then tan−1 x + tan−1 y equals

 

Options

  • `pi/2`

  • `-pi/2`

  • − π

  • none of these

MCQ
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Solution

(b) `-pi/2`
We know that 
\[\tan^{- 1} x + \tan^{- 1} y = \tan^{- 1} \left( \frac{x + y}{1 - xy} \right)\]
\[x < 0, y < 0\]  such that
xy = 1
Let x = -a and y = -b, where a and b both are positive.
\[\therefore \tan^{- 1} x + \tan^{- 1} y = \tan^{- 1} \left( \frac{x + y}{1 - xy} \right)\]
\[ = \tan^{- 1} \left( \frac{- a - a}{1 - 1} \right)\]
\[ = \tan^{- 1} \left( - \infty \right)\]
\[ = \tan^{- 1} \left\{ \tan\left( - \frac{\pi}{2} \right) \right\}\]
\[ = - \frac{\pi}{2}\]

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.16 [Page 120]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 11 | Page 120

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