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प्रश्न
Evaluate the following:
`cos^-1{cos (13pi)/6}`
उत्तर
We know
`cos^-1(costheta)=thetaif 0<=theta<=pi`
We have
`cos^-1{cos (13pi)/6}=cos^-1{cos(2pi+pi/6)}`
`= cos^-1{cos(pi/6)}`
`=pi/6`
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