हिंदी

Evaluate the Following: `Cos^-1(Cos3)` - Mathematics

Advertisements
Advertisements

प्रश्न

Evaluate the following:

`cos^-1(cos3)`

उत्तर

We know

`cos^-1(costheta)=thetaif 0<=theta<=pi`

We have

`cos^-1(cos3)=3`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Inverse Trigonometric Functions - Exercise 4.07 [पृष्ठ ४२]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.07 | Q 2.5 | पृष्ठ ४२

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Solve the equation for x:sin1x+sin1(1x)=cos1x


​Find the principal values of the following:

`cos^-1(tan  (3pi)/4)`


`sin^-1(sin  pi/6)`


Evaluate the following:

`tan^-1(tan  (9pi)/4)`


Evaluate the following:

`tan^-1(tan2)`


Evaluate the following:

`tan^-1(tan4)`


Evaluate the following:

`\text(cosec)^-1(\text{cosec}  pi/4)`


Evaluate the following:

`sin(sec^-1  17/8)`


Evaluate the following:

`cosec(cos^-1  3/5)`


Evaluate the following:

`cot(cos^-1  3/5)`


Prove the following result

`tan(cos^-1  4/5+tan^-1  2/3)=17/6`


Evaluate:

`cos(sec^-1x+\text(cosec)^-1x)`,|x|≥1


`sin(sin^-1  1/5+cos^-1x)=1`


Prove the following result:

`tan^-1  1/7+tan^-1  1/13=tan^-1  2/9`


`sin^-1  63/65=sin^-1  5/13+cos^-1  3/5`


`tan^-1  1/7+2tan^-1  1/3=pi/4`


`sin^-1  4/5+2tan^-1  1/3=pi/2`


If x < 0, then write the value of cos−1 `((1-x^2)/(1+x^2))` in terms of tan−1 x.


Write the value of tan1x + tan−1 `(1/x)`for x > 0.


Write the value of tan1 x + tan−1 `(1/x)`  for x < 0.


Write the value of sin (cot−1 x).


Evaluate sin

\[\left( \frac{1}{2} \cos^{- 1} \frac{4}{5} \right)\]


Write the value of cos1 (cos 350°) − sin−1 (sin 350°)


Write the value of sin \[\left\{ \frac{\pi}{3} - \sin^{- 1} \left( - \frac{1}{2} \right) \right\}\]


Write the value ofWrite the value of \[2 \sin^{- 1} \frac{1}{2} + \cos^{- 1} \left( - \frac{1}{2} \right)\]


Show that \[\sin^{- 1} (2x\sqrt{1 - x^2}) = 2 \sin^{- 1} x\]


If \[\cos\left( \tan^{- 1} x + \cot^{- 1} \sqrt{3} \right) = 0\] , find the value of x.

 

2 tan−1 {cosec (tan−1 x) − tan (cot1 x)} is equal to


If  \[\cos^{- 1} \frac{x}{a} + \cos^{- 1} \frac{y}{b} = \alpha, then\frac{x^2}{a^2} - \frac{2xy}{ab}\cos \alpha + \frac{y^2}{b^2} = \]


If sin−1 − cos−1 x = `pi/6` , then x = 


If \[\cos^{- 1} \frac{x}{2} + \cos^{- 1} \frac{y}{3} = \theta,\]  then 9x2 − 12xy cos θ + 4y2 is equal to


If \[\cos^{- 1} x > \sin^{- 1} x\], then


The domain of  \[\cos^{- 1} \left( x^2 - 4 \right)\] is

 


If x = a (2θ – sin 2θ) and y = a (1 – cos 2θ), find \[\frac{dy}{dx}\] When  \[\theta = \frac{\pi}{3}\] .


Write the value of \[\cos^{- 1} \left( - \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\] .


The period of the function f(x) = tan3x is ____________.


The value of sin `["cos"^-1 (7/25)]` is ____________.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×