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प्रश्न
`sin^-1 63/65=sin^-1 5/13+cos^-1 3/5`
उत्तर
RHS
`sin^-1 5/13+cos^-1 3/5`
`=sin^-1 5/13+sin^-1 4/5` `[because cos^-1x=sin^-1sqrt(1-x^2)]`
`=sin^-1{5/13sqrt(1-(4/5)^2)+4/5sqrt(1-(5/13)^2)}`
`=sin^-1{5/13xx3/5+4/5xx12/13}`
`=sin^-1{15/65+48/65}`
`=sin^-1 63/65=`LHS
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