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प्रश्न
Find the value of the following:
`cos(sec^-1x+\text(cosec)^-1x),` | x | ≥ 1
उत्तर
We have
`cos(sec^-1x+\text(cosec)^-1x)`
`=cos pi/2` `[becausesec^-1x+\text(cosec)^-1x=pi/2]`
= 0
`thereforecos(sec^-1x+\text(cosec)^-1x)=0` , ∣ x ∣ ≥1
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