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प्रश्न
Evaluate the following:
`cos(tan^-1 24/7)`
उत्तर
`cos(tan^-1 24/7)=cos[cos^-1 1/sqrt(1+(24/7)^2)]` `[therefore tan^-1x=cos^-1 1/sqrt(1+z^2)]`
`=cos[cos^-1 1/sqrt(1+576/49)]`
`=cos[cos^-1 1/(25/7)]`
`=cos[cos^-1 7/25]`
`=7/25`
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