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प्रश्न
`5tan^-1x+3cot^-1x=2x`
उत्तर
`5tan^-1x+3cot^-1x=2x`
⇒ `5tan^-1x+3(pi/2-tan^-1x)=2pi` `[becausecot^-1x=pi/2-tan^-1x]`
⇒ `5tan^-1x+(3pi)/2-3tan^-1x=2pi`
⇒ `2tan^-1x=pi/2`
⇒ `tan^-1x=pi/4`
⇒ `x=tan pi/4=1`
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