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प्रश्न
Evaluate:
`cot{sec^-1(-13/5)}`
उत्तर
`cot{sec^-1(-13/5)}=cot{sec^-1(pi-13/5)}`
`=-cot{sec^-1(13/5)}`
`=-cot{tan^-1(sqrt(1-(5/13)^3)/(5/13))}`
`=-cot{tan^-1(12/5)}`
`=-cot{cot^-1(5/12)}`
`=-5/12`
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