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प्रश्न
Evaluate the following:
`cot^-1{cot (-(8pi)/3)}`
उत्तर
We know that
cot-1 (cot θ) = θ, (0, π)
We have
`cot^-1{cot -((8pi)/3)}=cot^-1[-cot((8pi)/3)]`
`=cot^-1[-cot(3pi-pi/3)]`
`=cot^-1(cot pi/3)`
`=pi/3`
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