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Prove that: sin (2 × 30°) = 2tan30°1+tan230° - Mathematics

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प्रश्न

prove that:

sin (2 × 30°) = `(2 tan 30°)/(1+tan^2 30°)`

योग

उत्तर

RHS = `(2 tan 30°)/(1+tan^2 30°) = (2xx1/(sqrt3))/(1 +(1/sqrt3)^2) = (2/(sqrt3))/(1+(1)/(3)) = (2/sqrt3)/(4/(3)) =2/sqrt3xx3/4=3/(2sqrt3)xxsqrt3/sqrt3=(3sqrt3)/(2xx3)= (sqrt3)/(2)`

LHS = sin (2 × 30°) = sin 60° = `(sqrt3)/(2)`

∴ LHS = RHS

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अध्याय 23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios] - Exercise 23 (A) [पृष्ठ २९१]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (A) | Q 4.1 | पृष्ठ २९१

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