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Without using tables, evaluate the following: cosec245° sec230° - sin230° - 4cot245° + sec260°. - Mathematics

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प्रश्न

Without using tables, evaluate the following: cosec245° sec230° - sin230° - 4cot245° + sec260°.

योग

उत्तर

cosec245° sec230° - sin230° - 4cot245° + sec260°.

sin45° = `(1)/sqrt(2)`

cosec45° = `sqrt(2)/(1)`

sin30° = `(1)/(2)` = cos60°

sec60° = 2

cos30° = `sqrt(3)/(2)`

sec30° = `(2)/sqrt(3)`

tan45° = 1
cot45° = 1
cosec245° sec230° - sin230° - 4cot245° + sec260°

= `(sqrt(2)/1)^2 (2/sqrt(3))^2 - (1/2)^2 - 4(1)^2 + (2)^2`

= `2 xx (4)/(3) - (1)/(4) - 4 + 4`

= `(8)/(3) - (1)/(4)`

= `(32 - 3)/(12)`

= `(29)/(12)`.

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अध्याय 27: Trigonometrical Ratios of Standard Angles - Exercise 27.1

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 27 Trigonometrical Ratios of Standard Angles
Exercise 27.1 | Q 1.07

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