मराठी

Find the General Solution of the Following Equation: Tan 3 X = Cot X - Mathematics

Advertisements
Advertisements

प्रश्न

Find the general solution of the following equation:

\[\tan 3x = \cot x\]
बेरीज

उत्तर

We have:

\[\tan3x = \cot x\]

\[\Rightarrow \tan3x = \tan \left( \frac{\pi}{2} - x \right)\]

\[ \Rightarrow 3x = n\pi + \left( \frac{\pi}{2} - x \right), n \in Z\]

\[ \Rightarrow 4x = n\pi + \frac{\pi}{2}, n \in Z\]

\[ \Rightarrow x = \frac{n\pi}{4} + \frac{\pi}{8}, n \in Z\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Trigonometric equations - Exercise 11.1 [पृष्ठ २१]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
पाठ 11 Trigonometric equations
Exercise 11.1 | Q 2.06 | पृष्ठ २१

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the general solution of the equation cos 4 x = cos 2 x


Find the general solution of the equation cos 3x + cos x – cos 2x = 0


If \[cosec x - \sin x = a^3 , \sec x - \cos x = b^3\], then prove that \[a^2 b^2 \left( a^2 + b^2 \right) = 1\]


If \[T_n = \sin^n x + \cos^n x\], prove that \[\frac{T_3 - T_5}{T_1} = \frac{T_5 - T_7}{T_3}\]

 


Prove that:
\[\tan 4\pi - \cos\frac{3\pi}{2} - \sin\frac{5\pi}{6}\cos\frac{2\pi}{3} = \frac{1}{4}\]


Prove that:

\[\tan\frac{5\pi}{4}\cot\frac{9\pi}{4} + \tan\frac{17\pi}{4}\cot\frac{15\pi}{4} = 0\]

 


If \[\frac{\pi}{2} < x < \frac{3\pi}{2},\text{ then }\sqrt{\frac{1 - \sin x}{1 + \sin x}}\] is equal to

 


If \[0 < x < \frac{\pi}{2}\], and if \[\frac{y + 1}{1 - y} = \sqrt{\frac{1 + \sin x}{1 - \sin x}}\], then y is equal to


If tan x + sec x = \[\sqrt{3}\], 0 < x < π, then x is equal to


\[\sec^2 x = \frac{4xy}{(x + y )^2}\] is true if and only if

 


If A lies in second quadrant 3tan A + 4 = 0, then the value of 2cot A − 5cosA + sin A is equal to


The value of \[\cos1^\circ \cos2^\circ \cos3^\circ . . . \cos179^\circ\] is

 

The value of \[\tan1^\circ \tan2^\circ \tan3^\circ . . . \tan89^\circ\] is

 

Which of the following is correct?


Find the general solution of the following equation:

\[\cos x = - \frac{\sqrt{3}}{2}\]

Find the general solution of the following equation:

\[\sin 2x = \frac{\sqrt{3}}{2}\]

Find the general solution of the following equation:

\[\tan x + \cot 2x = 0\]

Find the general solution of the following equation:

\[\tan 2x \tan x = 1\]

Find the general solution of the following equation:

\[\sin x = \tan x\]

Solve the following equation:

\[4 \sin^2 x - 8 \cos x + 1 = 0\]

Solve the following equation:

\[\cos x \cos 2x \cos 3x = \frac{1}{4}\]

Solve the following equation:

\[\sin x + \sin 2x + \sin 3x + \sin 4x = 0\]

Solve the following equation:

\[\tan x + \tan 2x = \tan 3x\]

Solve the following equation:

`cosec  x = 1 + cot x`


Solve the following equation:
\[5 \cos^2 x + 7 \sin^2 x - 6 = 0\]


Solve the following equation:
4sinx cosx + 2 sin x + 2 cosx + 1 = 0 


Solve the following equation:
 sin x tan x – 1 = tan x – sin x

 


Write the number of solutions of the equation
\[4 \sin x - 3 \cos x = 7\]


Write the number of points of intersection of the curves

\[2y = 1\] and \[y = \cos x, 0 \leq x \leq 2\pi\].
 

The smallest value of x satisfying the equation

\[\sqrt{3} \left( \cot x + \tan x \right) = 4\] is 

If a is any real number, the number of roots of \[\cot x - \tan x = a\] in the first quadrant is (are).


The number of values of ​x in [0, 2π] that satisfy the equation \[\sin^2 x - \cos x = \frac{1}{4}\]


If \[\sqrt{3} \cos x + \sin x = \sqrt{2}\] , then general value of x is


Find the principal solution and general solution of the following:
tan θ = `- 1/sqrt(3)`


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

2 cos2x + 1 = – 3 cos x


Solve the following equations:
sin 5x − sin x = cos 3


Solve the following equations:
sin θ + cos θ = `sqrt(2)`


Solve the following equations:
cos 2θ = `(sqrt(5) + 1)/4`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×