Find the General Solution of the Following Equation: Sin 2 X = √ 3 2 - Mathematics

प्रश्न

Find the general solution of the following equation:

\sin 2 x = \frac{\sqrt{3}}{2}

बेरीज

उत्तर

We have:

\sin 2 x = \frac{\sqrt{3}}{2}

⇒ $\sin 2 x = \sin \frac{π}{3}$

⇒ $2 x = n π + (- 1)^{n} \frac{π}{3}$

n \in Z

⇒ $x = \frac{n π}{2} + (- 1)^{n} \frac{π}{6}$ ,

n \in Z

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Trigonometric Equations

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Q 2.01 Q 1.6 Q 2.02

पाठ 11: Trigonometric equations - Exercise 11.1 [पृष्ठ २१]

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आरडी शर्मा Mathematics [English] Class 11

पाठ 11 Trigonometric equations
Exercise 11.1 | Q 2.01 | पृष्ठ २१

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Find the General Solution of the Following Equation: Sin 2 X = √ 3 2 - Mathematics

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