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प्रश्न
Find the general solution of the following equation:
उत्तर
We have:
⇒ \[\sin2x = \sin \frac{\pi}{3}\]
⇒ \[2x = n\pi + ( - 1 )^n \frac{\pi}{3}\]
⇒ \[x = \frac{n\pi}{2} + ( - 1 )^n \frac{\pi}{6}\],
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