Advertisements
Advertisements
Question
Find the derivative of x–4 (3 – 4x–5).
Solution
Let f(x) = x–4 (3 – 4x–5)
By Leibnitz product rule,
f'(x) =
= x-4 {0 - 4 (-5) x-5-1} + (3 - 4x-5) (-4) x-4-1
= x-4 (20x-6) + (3 - 4x-5) (-4x-5)
= 20x-10 + 12x-5 + 16x-10
= 36x-10 - 12x-5
=
APPEARS IN
RELATED QUESTIONS
Find the derivative of
Find the derivative of x5 (3 – 6x–9).
Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):
(ax + b)n (cx + d)m
Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):
Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):
x4 (5 sin x – 3 cos x)
Find the derivative of f (x) = 99x at x = 100
x2 + x + 3
(x + 2)3
x ex
Differentiate each of the following from first principle:
Differentiate each of the following from first principle:
Differentiate each of the following from first principle:
Differentiate each of the following from first principle:
tan 2x
a0 xn + a1 xn−1 + a2 xn−2 + ... + an−1 x + an.
cos (x + a)
If for f (x) = λ x2 + μ x + 12, f' (4) = 15 and f' (2) = 11, then find λ and μ.
x5 ex + x6 log x
logx2 x
(ax + b) (a + d)2
(ax + b)n (cx + d)n
Write the value of
If x < 2, then write the value of
If f (x) =