Advertisements
Advertisements
Question
Find the domain of `f(x) =2cos^-1 2x+sin^-1x.`
Solution
For `2cos^-1 2x` to be defined.
`-1<=2x<=1`
`=>-1/2<=x<=1/2` .....(i)
For `sin^-1x` to be defined.
`-1<=x<=1` .....(ii)
Domain of `f(x) = [-1/2,1/2]cap[-1,1]`
`=[-1/2,1/2]`.
APPEARS IN
RELATED QUESTIONS
If `tan^(-1)((x-2)/(x-4)) +tan^(-1)((x+2)/(x+4))=pi/4` ,find the value of x
If a line makes angles 90° and 60° respectively with the positive directions of x and y axes, find the angle which it makes with the positive direction of z-axis.
`sin^-1(sin (5pi)/6)`
Evaluate the following:
`cos^-1(cos12)`
Evaluate the following:
`cosec^-1(cosec (6pi)/5)`
Evaluate the following:
`cot^-1{cot ((21pi)/4)}`
Write the following in the simplest form:
`tan^-1{(sqrt(1+x^2)-1)/x},x !=0`
Evaluate the following:
`sin(tan^-1 24/7)`
Prove the following result
`cos(sin^-1 3/5+cot^-1 3/2)=6/(5sqrt13)`
Evaluate:
`cot{sec^-1(-13/5)}`
Evaluate:
`tan{cos^-1(-7/25)}`
Evaluate: `sin{cos^-1(-3/5)+cot^-1(-5/12)}`
If `sin^-1x+sin^-1y=pi/3` and `cos^-1x-cos^-1y=pi/6`, find the values of x and y.
Prove the following result:
`tan^-1 1/7+tan^-1 1/13=tan^-1 2/9`
Prove the following result:
`tan^-1 1/4+tan^-1 2/9=sin^-1 1/sqrt5`
Solve the following equation for x:
tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x
Solve the following equation for x:
`tan^-1(2+x)+tan^-1(2-x)=tan^-1 2/3, where x< -sqrt3 or, x>sqrt3`
Solve the following:
`sin^-1x+sin^-1 2x=pi/3`
Evaluate the following:
`tan{2tan^-1 1/5-pi/4}`
Write the value of sin−1 (sin 1550°).
Write the value of cos−1 (cos 350°) − sin−1 (sin 350°)
Write the value of cos−1 (cos 6).
If \[\tan^{- 1} (\sqrt{3}) + \cot^{- 1} x = \frac{\pi}{2},\] find x.
Write the value of \[\sin^{- 1} \left( \frac{1}{3} \right) - \cos^{- 1} \left( - \frac{1}{3} \right)\]
Write the principal value of `sin^-1(-1/2)`
Write the value of \[\tan^{- 1} \left\{ 2\sin\left( 2 \cos^{- 1} \frac{\sqrt{3}}{2} \right) \right\}\]
Write the value of \[\sec^{- 1} \left( \frac{1}{2} \right)\]
The set of values of `\text(cosec)^-1(sqrt3/2)`
Write the value of \[\tan^{- 1} \left( \frac{1}{x} \right)\] for x < 0 in terms of `cot^-1x`
Find the value of \[\cos^{- 1} \left( \cos\frac{13\pi}{6} \right)\]
If \[\tan^{- 1} \left( \frac{\sqrt{1 + x^2} - \sqrt{1 - x^2}}{\sqrt{1 + x^2} + \sqrt{1 - x^2}} \right)\] = α, then x2 =
If \[\cos^{- 1} \frac{x}{a} + \cos^{- 1} \frac{y}{b} = \alpha, then\frac{x^2}{a^2} - \frac{2xy}{ab}\cos \alpha + \frac{y^2}{b^2} = \]
The positive integral solution of the equation
\[\tan^{- 1} x + \cos^{- 1} \frac{y}{\sqrt{1 + y^2}} = \sin^{- 1} \frac{3}{\sqrt{10}}\text{ is }\]
If tan−1 3 + tan−1 x = tan−1 8, then x =
If \[\cos^{- 1} x > \sin^{- 1} x\], then
The value of sin \[\left( \frac{1}{4} \sin^{- 1} \frac{\sqrt{63}}{8} \right)\] is
The value of \[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right)\]
The value of sin `["cos"^-1 (7/25)]` is ____________.