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If show thatdydxlog10(x3-y3x3+y3)=2,show thatdydx=-99x2101y2 - Mathematics and Statistics

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Question

If `log_10((x^3 - y^3)/(x^3 + y^3)) = 2, "show that" "dy"/"dx" = -(99x^2)/(101y^2)`

Sum

Solution

`log_10((x^3 - y^3)/(x^3 + y^3))` = 2

∴ `(x^3 - y^3)/(x^3 + y^3)` = 102 = 100
∴ x3 – y3 = 100x3 + 100y3
∴ 101y3 = – 99x3
∴ y3 = `(-99)/(101)x^3`
Differentiating both sides w.r.t. x, we get 
`3y^2"dy"/"dx" = (-99)/(101) xx 3x^2`

∴ `"dy"/"dx" = -(99x^2)/(101y^2`.

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Chapter 1: Differentiation - Exercise 1.3 [Page 40]

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