English

Write a Value of ∫ √ 4 − X 2 D X - Mathematics

Advertisements
Advertisements

Question

Write a value of\[\int\sqrt{4 - x^2} \text{ dx }\]

Sum

Solution

\[\int \sqrt{4 - x^2} dx\]
\[ = \int \sqrt{2^2 - x^2}   \text{ dx }\]
\[ = \frac{x}{2}\sqrt{2^2 - x^2} + \frac{2^2}{2} \sin^{- 1} \left( \frac{x}{2} \right) + C \left( \because \sqrt{a^2 - x^2} = \frac{x}{2}\sqrt{a^2 - x^2} - \frac{a^2}{2} \sin^{- 1} \frac{x}{a} + C \right)\]
\[ = \frac{x}{2}\sqrt{4 - x^2} + 2 \sin^{- 1} \left( \frac{x}{2} \right) + C\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 19: Indefinite Integrals - Very Short Answers [Page 198]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Very Short Answers | Q 35 | Page 198

RELATED QUESTIONS

Integrate the functions:

(4x + 2) `sqrt(x^2 + x +1)`


Integrate the functions:

`x/(sqrt(x+ 4))`, x > 0 


Evaluate: `int 1/(x(x-1)) dx`


Evaluate: `int (2y^2)/(y^2 + 4)dx`


\[\int\sqrt{x^2 + x + 1} \text{ dx}\]

Write a value of\[\int \log_e x\ dx\].

 


Write a value of\[\int\frac{\sin x - \cos x}{\sqrt{1 + \sin 2x}} \text{ dx}\]


Write a value of\[\int e^{ax} \cos\ bx\ dx\].

 


Write a value of\[\int e^{ax} \left\{ a f\left( x \right) + f'\left( x \right) \right\} dx\] .


Evaluate the following integrals : tan2x dx


Evaluate the following integrals : `intsqrt(1 - cos 2x)dx`


Integrate the following functions w.r.t. x : `(x.sec^2(x^2))/sqrt(tan^3(x^2)`


Integrate the following functions w.r.t. x : `sqrt(tanx)/(sinx.cosx)`


Integrate the following functions w.r.t. x : `((x - 1)^2)/(x^2 + 1)^2`


Integrate the following functions w.r.t. x : `(2x + 1)sqrt(x + 2)`


Evaluate the following : `int (1)/(5 - 4x - 3x^2).dx`


Evaluate the following : `int (1)/sqrt(8 - 3x + 2x^2).dx`


Evaluate the following : `int (1)/(cos2x + 3sin^2x).dx`


Integrate the following functions w.r.t. x : `int (1)/(cosx - sqrt(3)sinx).dx`


Evaluate the following integrals :  `int (3x + 4)/sqrt(2x^2 + 2x + 1).dx`


If f '(x) = `"x"^2/2 - "kx" + 1`, f(0) = 2 and f(3) = 5, find f(x).


Evaluate the following.

`int 1/(sqrt("x"^2 + 4"x"+ 29))` dx


Choose the correct alternative from the following.

The value of `int "dx"/sqrt"1 - x"` is


`int (x^2 + x - 6)/((x - 2)(x - 1))dx = x` + ______ + c


Evaluate `int 1/((2"x" + 3))` dx


Evaluate: `int 1/(2"x" + 3"x" log"x")` dx


`int logx/x  "d"x`


`int "e"^x[((x + 3))/((x + 4)^2)] "d"x`


`int cot^2x  "d"x`


`int(5x + 2)/(3x - 4) dx` = ______


`int(sin2x)/(5sin^2x+3cos^2x)  dx=` ______.


`int (sin  (5x)/2)/(sin  x/2)dx` is equal to ______. (where C is a constant of integration).


The value of `sqrt(2) int (sinx  dx)/(sin(x - π/4))` is ______.


If `int [log(log x) + 1/(logx)^2]dx` = x [f(x) – g(x)] + C, then ______.


Find `int (x + 2)/sqrt(x^2 - 4x - 5) dx`.


Evaluate.

`int(5"x"^2 - 6"x" + 3)/(2"x" - 3)  "dx"`


Evaluate `int(1+x+(x^2)/(2!))dx`


If f '(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate `int(5x^2-6x+3)/(2x-3)dx`


Evaluate the following.

`int1/(x^2 + 4x - 5)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×