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Question
Verify the following:
`int (x - 1)/(2x + 3) "d"x = x - log |(2x + 3)^2| + "C"`
Solution
L.H.S. = `int (2x - 1)/(2x + 3) "d"x`
⇒ `int (1 - 4/(2x + 3)) "d"x` .....[Dividing the numerator by the denominator]
⇒ `int 1 * "d"x - 4 int 1/(2x + 3) "d"x`
⇒ `int 1 * "d"x - 4/2 int 1/(x + 3/2) "d"x`
⇒ `int 1 * "d"x - 2 int 1/(x + 3/2) "d"x`
⇒ `x - 2 log |x + 3/2| + "C"`
⇒ `x - 2 log |(2x + 3)/2| + "C"`
⇒ `x - log|((2x + 3)/2)^2| + "C"` ....[∵ n log m = log mn]
⇒ `x - log |(2x + 3)^2| - log 2^2 + "C"`
⇒ `x - log |(2x + 3)^2| + "C"_1`
⇒ R.H.S. ......[Where C1 = C – log 22]
L.H.S. = R.H.S.
Hence proved.
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