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प्रश्न
Integrate the functions:
`sqrt(ax + b)`
उत्तर
Let `I = int sqrt(ax + b) dx`
Put ax + b = t
a dx = dt
`=> dx = 1/a dt`
Hence, `I = int 1/a sqrtt dt`
`= 1/a int t^(1/2) dt`
`= 1/a . 2/3 t^(3/2) + C`
`= 2/(3a) (ax + b)^(3/2) + C`
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