English

Without using tables, evaluate the following: (sin90° + sin45° + sin30°)(sin90° - cos45° + cos60°). - Mathematics

Advertisements
Advertisements

Question

Without using tables, evaluate the following: (sin90° + sin45° + sin30°)(sin90° - cos45° + cos60°).

Sum

Solution

(sin90° + sin45° + sin30°)(sin90° - cos45° + cos60°).

sin30° = `(1)/(2)`

sin45° = `(1)/sqrt(2)`
sin90° = 1

cos45° = `(1)/sqrt(2)`

cos60° = `(1)/(2)`
(sin90° + sin45° + sin30°)(sin90° - cos45° + cos60°)

= `(1 + 1/sqrt(2) + 1/sqrt(2))(1 - 1/sqrt(2) + 1/sqrt(2))`

= `(3/2 + 1/sqrt(2))(3/2 - 1/sqrt(2))`

= `(3/2)^2 - (1/sqrt(2))^2`

= `(9)/(4) - (1)/(2)`

= `(9 - 2)/(4)`

= `(7)/(4)`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 27: Trigonometrical Ratios of Standard Angles - Exercise 27.1

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 27 Trigonometrical Ratios of Standard Angles
Exercise 27.1 | Q 1.09

RELATED QUESTIONS

If A, B and C are interior angles of a triangle ABC, then show that `\sin( \frac{B+C}{2} )=\cos \frac{A}{2}`


Evaluate the following in the simplest form: sin 60º cos 45º + cos 60º sin 45º


Evaluate the following:

`(cos 45°)/(sec 30° + cosec  30°)`


Evaluate the following:

`(5cos^2 60° +  4sec^2 30° - tan^2 45°)/(sin^2 30° +  cos^2 30°)`


Show that tan 48° tan 23° tan 42° tan 67° = 1


Evaluate the following :

`((sin 27^@)/(cos 63^@))^2 - (cos 63^@/sin 27^@)^2`


Evaluate the following :

sin 35° sin 55° − cos 35° cos 55°


Express each one of the following in terms of trigonometric ratios of angles lying between 0° and 45°

sec 76° + cosec 52°


Express cos 75° + cot 75° in terms of angles between 0° and 30°.


If A, B, C are the interior angles of a triangle ABC, prove that

`tan ((C+A)/2) = cot  B/2`


Prove that `cos 80^@/sin 10^@  + cos 59^@ cosec 31^@ = 2`


Evaluate: tan 7° tan 23° tan 60° tan 67° tan 83°


Evaluate: 

`(cos3"A" – 2cos4"A")/(sin3"A" + 2sin4"A")` , when A = 15°


If A =30o, then prove that :
sin 2A = 2sin A cos A =  `(2 tan"A")/(1 + tan^2"A")`


Prove that:

cos2 30°  - sin2 30° = cos 60°


Prove that:

4 (sin4 30° + cos4 60°) -3 (cos2 45° - sin2 90°) = 2


secθ . Cot θ= cosecθ ; write true or false


Evaluate : 

`(3 sin 3"B" + 2 cos(2"B" + 5°))/(2 cos 3"B" – sin (2"B" – 10°)` ; when "B" = 20°.


Given A = 60° and B = 30°,

prove that: tan (A - B) = `(tan"A"  –  tan"B")/(1 + tan"A".tan"B")`


If A =30o, then prove that :
sin 3A = 3 sin A - 4 sin3A.


If A = 30°;
show that:
`(1 – cos 2"A")/(sin 2"A") = tan"A"`


If A = 30°;
show that:
4 cos A cos (60° - A). cos (60° + A) = cos 3A


Without using tables, evaluate the following: sec30° cosec60° + cos60° sin30°.


Without using tables, evaluate the following: sin230° cos245° + 4tan230° + sin290° + cos2


Prove that : sec245° - tan245° = 1


If A = B = 45°, verify that sin (A - B) = sin A .cos B - cos A.sin B


If sin(A - B) = sinA cosB - cosA sinB and cos(A - B) = cosA cosB + sinA sinB, find the values of sin15° and cos15°.


If sin 30° = x and cos 60° = y, then x2 + y2 is


The value of `(1 - tan^2 45^circ)/(1 + tan^2 45^circ)` is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×