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Evaluate d∫1+x1-xdx, x ≠1 - Mathematics

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प्रश्न

Evaluate `int sqrt((1 + x)/(1 - x)) "d"x`, x ≠1

योग

उत्तर

Let I = `int sqrt((1 + x)/(1 - x)) "d"x`

= `int 1/sqrt(1 - x^2) "d"x + int (x"d"x)/sqrt(1 - x^2)`

= `sin^-1x + 1`

When I1 = `(x"d"x)/sqrt(1 - x^2)`.

Put 1 – x2 = t2

⇒ –2x dx = 2t dt.

Therefore I1 = – dt = – t + C

= `- sqrt(1 - x^2) + "C"`

Hence I = `sin^-1x - sqrt(1 - x^2) + "C"`.

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Definite Integrals
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अध्याय 7: Integrals - Solved Examples [पृष्ठ १४७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 7 Integrals
Solved Examples | Q 4 | पृष्ठ १४७

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