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प्रश्न
Integrate : sec3 x w. r. t. x.
उत्तर
`I = intsec^3x dx`
`I =int secx.sec^2x dx`
`I =secx.intsec^2xdx-int[d/dx(secx).int sec^2x dx] dx`
`I =secx.tanx-int secx.tanx.tanx dx`
`I =secx.tanx-int secx(sec^2x -1)dx`
`I =secx.tanx-int [sec^3x-secx]dx`
`I =secx.tanx-int sec^3x + int secxdx`
`I =secx.tanx - I + log|secx + tanx| + c`
`2I =secx.tanx + log|secx + tanx| + c`
`therefore I =1/2(secx.tanx + log|secx + tanx|) + c`
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