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Question
Evaluate `int (3"a"x)/("b"^2 + "c"^2x^2) "d"x`
Solution
Let v = b2 + c2x2, then dv = 2c2 xdx
Therefore, `int (3"a"x)/("b"^2 + "c"^2x^2) "d"x`
= `(3"a")/(2"c"^2) int "dv"/"v"`
= `(3"a")/("c"^2) log |"b"^2 + "c"^2x^2| + "C"`
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