English

Evaluate the Following: `Sin(Sec^-1 17/8)` - Mathematics

Advertisements
Advertisements

Question

Evaluate the following:

`sin(sec^-1  17/8)`

Solution

`=sin(sec^-1  17/8)=sin(cos^-1  8/17)`

`=sin[sin^-1sqrt(1-(8/17)^2)]`    `[thereforecos^-1x=sin^-1sqrt(1-x^2)]`

`=sin[sin^-1(sqrt(1-64/289))]`

`=sin[sin^-1(sqrt(225/289))]`

`=sin[sin^-1  15/17]`

`=15/17`

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.08 [Page 54]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.08 | Q 1.4 | Page 54

RELATED QUESTIONS

If tan-1x+tan-1y=π/4,xy<1, then write the value of x+y+xy.


Evaluate the following:

`tan^-1(tan  pi/3)`


Evaluate the following:

`tan^-1(tan12)`


Evaluate the following:

`sec^-1{sec  (-(7pi)/3)}`


Evaluate the following:

`cot^-1(cot  (19pi)/6)`


Write the following in the simplest form:

`cot^-1  a/sqrt(x^2-a^2),|  x  | > a`


Write the following in the simplest form:

`tan^-1{sqrt(1+x^2)-x},x in R `


Evaluate the following:

`sec(sin^-1  12/13)`


Evaluate the following:

`cot(cos^-1  3/5)`


Prove the following result

`cos(sin^-1  3/5+cot^-1  3/2)=6/(5sqrt13)`


Prove the following result-

`tan^-1  63/16 = sin^-1  5/13 + cos^-1  3/5`


Evaluate:

`sin(tan^-1x+tan^-1  1/x)` for x < 0


`5tan^-1x+3cot^-1x=2x`


Prove the following result:

`sin^-1  12/13+cos^-1  4/5+tan^-1  63/16=pi`


Solve the following equation for x:

 cot−1x − cot−1(x + 2) =`pi/12`, > 0


Solve the following equation for x:

tan−1(x + 2) + tan−1(x − 2) = tan−1 `(8/79)`, x > 0


Solve the following equation for x:

`tan^-1((x-2)/(x-4))+tan^-1((x+2)/(x+4))=pi/4`


If `cos^-1  x/2+cos^-1  y/3=alpha,` then prove that  `9x^2-12xy cosa+4y^2=36sin^2a.`


Solve `cos^-1sqrt3x+cos^-1x=pi/2`


`4tan^-1  1/5-tan^-1  1/239=pi/4`


Solve the following equation for x:

`3sin^-1  (2x)/(1+x^2)-4cos^-1  (1-x^2)/(1+x^2)+2tan^-1  (2x)/(1-x^2)=pi/3`


If x > 1, then write the value of sin−1 `((2x)/(1+x^2))` in terms of tan−1 x.


Write the value of tan1 x + tan−1 `(1/x)`  for x < 0.


What is the value of cos−1 `(cos  (2x)/3)+sin^-1(sin  (2x)/3)?`


Evaluate sin

\[\left( \frac{1}{2} \cos^{- 1} \frac{4}{5} \right)\]


Write the value of cos\[\left( \frac{1}{2} \cos^{- 1} \frac{3}{5} \right)\]


Write the value of \[\tan^{- 1} \frac{a}{b} - \tan^{- 1} \left( \frac{a - b}{a + b} \right)\]


Write the value of \[\tan\left( 2 \tan^{- 1} \frac{1}{5} \right)\]


Wnte the value of\[\cos\left( \frac{\tan^{- 1} x + \cot^{- 1} x}{3} \right), \text{ when } x = - \frac{1}{\sqrt{3}}\]


The value of tan \[\left\{ \cos^{- 1} \frac{1}{5\sqrt{2}} - \sin^{- 1} \frac{4}{\sqrt{17}} \right\}\] is

 


If  \[\cos^{- 1} \frac{x}{a} + \cos^{- 1} \frac{y}{b} = \alpha, then\frac{x^2}{a^2} - \frac{2xy}{ab}\cos \alpha + \frac{y^2}{b^2} = \]


The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]


The value of \[\cos^{- 1} \left( \cos\frac{5\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{5\pi}{3} \right)\] is

 


sin \[\left\{ 2 \cos^{- 1} \left( \frac{- 3}{5} \right) \right\}\]  is equal to

 


It \[\tan^{- 1} \frac{x + 1}{x - 1} + \tan^{- 1} \frac{x - 1}{x} = \tan^{- 1}\]   (−7), then the value of x is

 


If tan−1 (cot θ) = 2 θ, then θ =

 


The value of \[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right)\]

 


Solve for x : {xcos(cot-1 x) + sin(cot-1 x)}= `51/50`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×