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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 7

Division of Decimal Numbers - Division of a Decimal Number by Another Decimal Number

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Notes

Division of a Decimal Number by Another Decimal Number:

  • While dividing two decimal numbers, first shift the decimal point to the right by an equal number of places in both, to convert the divisor to a whole number. Then divide.
  • Thus, 2.4 ÷ 0.2 = 24 ÷ 2 = 12.

Let us find `(25.5)/(0.5)` i.e., 25.5 ÷ 0.5.

We have 25.5 ÷ 0.5 = `255/10 ÷ 5/10 = 255/10 xx 10/5 = 51`.

Thus, 25.5 ÷ 0.5 = 51.

For `25.5/0.5`, we find that there is one digit to the right of the decimal in 0.5. This could be converted to the whole number by dividing by 10. Accordingly, 25.5 was also converted to a fraction by dividing by 10.

Or, we say the decimal point was shifted by one place to the right in 0.5 to make it 5. So, there was a shift of one decimal point to the right in 25.5 also to make it 255.

Thus, 22.5 ÷ 1.5 = `22.5/1.5 = 225/15` = 15.

Example

Find: 6.6 ÷ 2.2

6.6 ÷ 2.2

`= 66/10 ÷ 22/10`

`= 66/10 xx 10/22`

`= (66 xx 10)/(10 xx 22)`

`= (10 xx 66)/(10 xx 22)`

`= 10/10 xx 66/22`

`= 1/1 xx 3`

= 3

Example

Find: 0.0125 ÷ 0.05

0.0125 ÷ 0.05

`= 125/10000 ÷ 5/100`

`= 125/10000 xx 100/5`

`= (125 xx 100)/(10000 xx 5)`

`= (100 xx 125)/(10000 xx 5)`

`= 100/10000 xx 125/5`

`= 1/100 xx 25`

`= (1 xx 25)/100`

`= 25/100`

= 0.25

Example

Find: 0.375 ÷ 1.5

0.375 ÷ 1.5

`= 375/1000 ÷ 15/10`

`= 375/1000 xx 10/15`

`= (375 xx 10)/(1000 xx 15)`

`= (10 xx 375)/(1000 xx 15)`

`= 10/1000 xx 375/15`

`= 1/100 xx 25`

`= (1 xx 25)/100`

`= 25/100`

= 0.25

Example

Each side of a regular polygon is 2.5 cm in length. The perimeter of the polygon is 12.5 cm. How many sides does the polygon have?

The perimeter of a regular polygon is the sum of the lengths of all its equal sides = 12.5 cm.
Length of each side = 2.5 cm.

Thus, the number of sides = `12.5/2.5 = 125/25 = 5`.

The polygon has 5 sides.

Example

A car covers a distance of 89.1 km in 2.2 hours. What is the average distance covered by it in 1 hour?

Distance covered by the car = 89.1 km.

Time required to cover this distance = 2.2 hours.

So distance covered by it in 1 hour = `(89.1)/2.2 = 891/22` = 40.5 km.

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