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प्रश्न
Evaluate the following:
`tan^-1(tan (6pi)/7)`
उत्तर
We know that
`tan^-1(tantheta)=theta, -pi/2<theta<pi/2`
We have
`tan^-1(tan (6pi)/7)=tan^-1[tan(pi+pi/7)]`
`=tan^-1[tan(-pi/7)]`
`=-pi/7`
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