हिंदी

Integrate the following w.r.t. x: x2+3(x2-1)(x2-2) - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Integrate the following w.r.t. x: `(x^2 + 3)/((x^2 - 1)(x^2 - 2)`

योग

उत्तर

Let I = `int (x^2 + 3)/((x^2 - 1)(x^2 - 2)).dx`

`(x^2 + 3)/((x^2 - 1)(x^2 - 2)) = "A"/(x^2 - 1) + "B"/(x^2 - 2)`

∴ x2 + 3 = A(x2 - 2) + B(x2 - 1)

Put x2 - 1 = 0 i. e. x2 = 1

∴ 1 + 3 = A(1 - 2) + B(1 - 1)

∴ 1 + 3 = A(1 - 2) + 0

∴ 4 = A × -1

∴ A = - 4

Put x2 - 2 = 0 i. e. x2 = 2

∴ `2 + 3 = 0 + B (2 - 1)`

∴ 5 = B × 1

∴ B = 5

I = `int (- 4)/(x^2 - 1^2) "dx" + int 5/(x^2 - (sqrt(2))^2)` dx

I = `- 4 xx 1/(2 xx 1) log |(x - 1)/(x + 1)| + 5 xx 1/(2 xx sqrt2)  log  |(x - sqrt2)/(x + sqrt2)|` + c    ...`[int 1/(x^2 - a^2) dx = 1/(2a) log |(x - a)/(x + a)| + "c"]`

I = `- 2 log |(x - 1)/(x + 1)| + 5/(2 sqrt2) log |(x - sqrt2)/(x + sqrt2)| + c`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.4 [पृष्ठ १४५]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.4 | Q 1.10 | पृष्ठ १४५

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Evaluate: `∫8/((x+2)(x^2+4))dx` 


Integrate the rational function:

`1/(x^2 - 9)`


Integrate the rational function:

`(3x - 1)/((x - 1)(x - 2)(x - 3))`


Integrate the rational function:

`x/((x-1)(x- 2)(x - 3))`


Integrate the rational function:

`x/((x^2+1)(x - 1))`


Integrate the rational function:

`x/((x -1)^2 (x+ 2))`


Integrate the rational function:

`(x^3 + x + 1)/(x^2 -1)`


Integrate the rational function:

`2/((1-x)(1+x^2))`


`int (dx)/(x(x^2 + 1))` equals:


Find `int(e^x dx)/((e^x - 1)^2 (e^x + 2))`


Find `int (2cos x)/((1-sinx)(1+sin^2 x)) dx`


Find : 

`∫ sin(x-a)/sin(x+a)dx`


Integrate the following w.r.t. x : `(x^2 + 2)/((x - 1)(x + 2)(x + 3)`


Integrate the following w.r.t. x : `x^2/((x^2 + 1)(x^2 - 2)(x^2 + 3))`


Integrate the following w.r.t. x : `(12x + 3)/(6x^2 + 13x - 63)`


Integrate the following w.r.t. x : `(2x)/(4 - 3x - x^2)`


Integrate the following w.r.t. x : `(x^2 + x - 1)/(x^2 + x - 6)`


Integrate the following w.r.t. x : `2^x/(4^x - 3 * 2^x - 4`


Integrate the following w.r.t. x : `(1)/(x(1 + 4x^3 + 3x^6)`


Integrate the following w.r.t. x : `(1)/(2sinx + sin2x)`


Integrate the following w.r.t. x : `(1)/(sin2x + cosx)`


Integrate the following w.r.t. x : `(2log x + 3)/(x(3 log x + 2)[(logx)^2 + 1]`


Choose the correct options from the given alternatives :

If `int tan^3x*sec^3x*dx = (1/m)sec^mx - (1/n)sec^n x + c, "then" (m, n)` =


Integrate the following with respect to the respective variable : `(6x + 5)^(3/2)`


Integrate the following w.r.t. x: `(2x^2 - 1)/(x^4 + 9x^2 + 20)`


Integrate the following w.r.t.x : `(1)/(2cosx + 3sinx)`


Integrate the following w.r.t.x:

`x^2/((x - 1)(3x - 1)(3x - 2)`


Integrate the following w.r.t.x : `(x + 5)/(x^3 + 3x^2 - x - 3)`


Integrate the following w.r.t.x : `sqrt(tanx)/(sinx*cosx)`


Evaluate: `int (2"x" + 1)/(("x + 1")("x - 2"))` dx


Evaluate: `int "3x - 2"/(("x + 1")^2("x + 3"))` dx


Evaluate: `int 1/("x"("x"^5 + 1))` dx


Evaluate: `int 1/("x"("x"^"n" + 1))` dx


For `int ("x - 1")/("x + 1")^3  "e"^"x" "dx" = "e"^"x"` f(x) + c, f(x) = (x + 1)2.


Evaluate: `int ("3x" - 1)/("2x"^2 - "x" - 1)` dx


Evaluate: `int (1 + log "x")/("x"(3 + log "x")(2 + 3 log "x"))` dx


`int "e"^(3logx) (x^4 + 1)^(-1) "d"x`


`int x^7/(1 + x^4)^2  "d"x`


`int x^2sqrt("a"^2 - x^6)  "d"x`


`int sqrt(4^x(4^x + 4))  "d"x`


`int sqrt((9 + x)/(9 - x))  "d"x`


`int 1/(4x^2 - 20x + 17)  "d"x`


`int "e"^(sin^(-1_x))[(x + sqrt(1 - x^2))/sqrt(1 - x^2)] "d"x`


`int (3x + 4)/sqrt(2x^2 + 2x + 1)  "d"x`


`int x^3tan^(-1)x  "d"x`


`int  x^2/((x^2 + 1)(x^2 - 2)(x^2 + 3))  "d"x`


`int (3"e"^(2x) + 5)/(4"e"^(2x) - 5)  "d"x`


`int  ((2logx + 3))/(x(3logx + 2)[(logx)^2 + 1])  "d"x`


Choose the correct alternative:

`int sqrt(1 + x)  "d"x` =


Choose the correct alternative:

`int (x + 2)/(2x^2 + 6x + 5) "d"x = "p"int (4x + 6)/(2x^2 + 6x + 5) "d"x + 1/2 int 1/(2x^2 + 6x + 5)"d"x`, then p = ?


Choose the correct alternative:

`int ((x^3 + 3x^2 + 3x + 1))/(x + 1)^5 "d"x` =


If f'(x) = `1/x + x` and f(1) = `5/2`, then f(x) = log x + `x^2/2` + ______ + c


Evaluate `int (2"e"^x + 5)/(2"e"^x + 1)  "d"x`


If `int(sin2x)/(sin5x  sin3x)dx = 1/3log|sin 3x| - 1/5log|f(x)| + c`, then f(x) = ______


Evaluate the following:

`int x^2/(1 - x^4) "d"x` put x2 = t


Evaluate the following:

`int (x^2"d"x)/(x^4 - x^2 - 12)`


Evaluate the following:

`int (x^2 "d"x)/((x^2 + "a"^2)(x^2 + "b"^2))`


Evaluate: `int (dx)/(2 + cos x - sin x)`


Find: `int x^2/((x^2 + 1)(3x^2 + 4))dx`


`int 1/(x^2 + 1)^2 dx` = ______.


If `int 1/((x^2 + 4)(x^2 + 9))dx = A tan^-1  x/2 + B tan^-1(x/3) + C`, then A – B = ______.


If `intsqrt((x - 5)/(x - 7))dx = Asqrt(x^2 - 12x + 35) + log|x| - 6 + sqrt(x^2 - 12x + 35) + C|`, then A = ______.


Find : `int (2x^2 + 3)/(x^2(x^2 + 9))dx; x ≠ 0`.


Evaluate:

`int(2x^3 - 1)/(x^4 + x)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×