\[\int\left( \sec^2 x + {cosec}^2 x \right) dx\]

\[\int\left( \sec^2 x + {cosec}^2 x \right)dx\]\[ = \int \sec^2\text{ x dx} + \int {cosec}^2\text{ x dx}\]\[ = \tan x - \cot x + C\]

∫ ( Sec 2 X + C O S E C 2 X ) D X - Mathematics

\int (\sec^{2} x + {c o s e c}^{2} x) d x

योग

$\int (\sec^{2} x + {c o s e c}^{2} x) d x$
$= \int \sec^{2} x dx + \int {c o s e c}^{2} x dx$
$= \tan x - \cot x + C$

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अध्याय 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १५]

अध्याय 19 Indefinite Integrals
Exercise 19.02 | Q 22 | पृष्ठ १५

\int \frac{1}{\sqrt{x}} (1 + \frac{1}{x}) d x

\int \frac{(x + 1) (x - 2)}{\sqrt{x}} d x

\int \frac{1}{1 - \sin x} d x

\int \frac{1}{\sqrt{2 x + 3} + \sqrt{2 x - 3}} d x

$\int \tan^{2} (2 x - 3) d x$

\int \sin^{2} b x dx

\int \frac{1}{\sqrt{1 + \cos x}} d x

\int \frac{1 - \cot x}{1 + \cot x} d x

\int \frac{\log (1 + \frac{1}{x})}{x (1 + x)} d x

$= \int \sqrt[3]{\cos^{2} x} \sin x d x$

\int \tan^{3 / 2} x \sec^{2} x dx

\int \frac{\sin (log x)}{x} d x

\int \frac{2 x - 1}{{(x - 1)}^{2}} d x

\int \frac{1}{\sqrt{x} + \sqrt[4]{x}} d x

\int \frac{1}{\sin^{3} x \cos^{5} x} d x

\int \frac{\cos x}{\sin^{2} x + 4 \sin x + 5} d x

\int \frac{1}{\sqrt{2 x - x^{2}}} d x

\int \frac{1}{\sqrt{8 + 3 x - x^{2}}} d x

\int \frac{1}{\sqrt{5 - 4 x - 2 x^{2}}} d x

\int \frac{1}{\sqrt{5 x^{2} - 2 x}} d x

\int \frac{x}{x^{2} + 3 x + 2} d x

\int \frac{x + 1}{x^{2} + x + 3} d x

\int \frac{x + 7}{3 x^{2} + 25 x + 28} dx

\int \frac{x^{2} + x + 1}{x^{2} - x} d x

\int \frac{1}{\cos 2 x + 3 \sin^{2} x} d x

\int \frac{1}{1 - \sin x + \cos x} dx

\int \frac{1}{\sqrt{3} \sin x + \cos x} d x

\int x \cos x d x

\int \sin^{- 1} \sqrt{x} dx

\int x \cos^{3} x d x

\int \tan^{- 1} \sqrt{\frac{1 - x}{1 + x}} d x

\int \frac{1}{x [6 {(\log x)}^{2} + 7 \log x + 2]} d x

\int \sqrt{\cot θ d} θ

\int \frac{1}{(x - 1) \sqrt{x^{2} + 1}} dx

$\int \sqrt{\frac{1 - x}{x}} dx$

$\int \frac{1}{2 + \cos x} dx$

\int \sqrt{1 + 2 x - 3 x^{2}} dx

\int x^{2} \tan^{- 1} x d x

\int \cos^{- 1} (1 - 2 x^{2}) dx