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प्रश्न
\[\int\left( \sec^2 x + {cosec}^2 x \right) dx\]
बेरीज
उत्तर
\[\int\left( \sec^2 x + {cosec}^2 x \right)dx\]
\[ = \int \sec^2\text{ x dx} + \int {cosec}^2\text{ x dx}\]
\[ = \tan x - \cot x + C\]
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