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Question
Find the principal value of `cot^-1 ((-1)/sqrt(3))`
Solution
Let y = `cot^-1 ((-1)/sqrt(3))`
Since, cot–1(– x) = π – cot–1x
∴ y = `π - cot^-1 (1/sqrt(3))`
⇒ y = `π - π/3` ......`(∵ cot π/3 = 1/sqrt(3))`
⇒ y = `(2π)/3`
Since, range of cot–1 is (0, π)
Hence, principal value is `(2π)/3`.
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