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Question
If `int_a^b x^3 dx` = 0, then `(x^4/square)_a^b` = 0
⇒ `1/4 (square - square)` = 0
⇒ b4 – `square` = 0
⇒ (b2 – a2)(`square` + `square`) = 0
⇒ b2 – `square` = 0 as a2 + b2 ≠ 0
⇒ b = ± `square`
Solution
`int_a^b x^3 dx` = 0, then `(x^4/bb4)_a^b` = 0
⇒ `1/4` (b4 – a4) = 0
⇒ b4 – a4 = 0
⇒ (b2 – a2)(b2 + a2) = 0
⇒ b2 – a2 = 0 as a2 + b2 ≠ 0
⇒ b = ± a
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