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Π / 2 ∫ π / 3 √ 1 + Cos X ( 1 − Cos X ) 5 / 2 D X - Mathematics

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प्रश्न

\[\int\limits_{\pi/3}^{\pi/2} \frac{\sqrt{1 + \cos x}}{\left( 1 - \cos x \right)^{5/2}} dx\]

योग

उत्तर

\[\int_\frac{\pi}{3}^\frac{\pi}{2} \frac{\sqrt{1 + \cos x}}{\left( 1 - \cos x \right)^\frac{5}{2}} d x\]

\[ = \int_\frac{\pi}{3}^\frac{\pi}{2} \frac{\sqrt{1 + \cos x}}{\left( 1 - \cos x \right)^\frac{5}{2}} \times \frac{\sqrt{1 - \cos x}}{\sqrt{1 - \cos x}} d x\]

\[ = \int_\frac{\pi}{3}^\frac{\pi}{2} \frac{\sin x}{\left( 1 - \cos x \right)^3}dx\]

\[ = - \frac{1}{2} \left[ \left( 1 - \cos x \right)^{- 2} \right]_\frac{\pi}{3}^\frac{\pi}{2} \]

\[ = - \frac{1}{2}\left[ 1 - 4 \right]\]

\[ = \frac{3}{2}\]

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Definite Integrals
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अध्याय 20: Definite Integrals - Revision Exercise [पृष्ठ १२१]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 20 Definite Integrals
Revision Exercise | Q 20 | पृष्ठ १२१

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