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प्रश्न
Evaluate the following:
`cot^-1(cot (9pi)/4)`
उत्तर
We know that
cot-1 (cot θ) = θ, (0, π)
We have
`cot^-1(cot (9pi)/4)=cot^-1[cot(2pi+pi/4)]`
`=cot^-1(cot pi/4)`
`=pi/4`
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