Advertisements
Advertisements
प्रश्न
Write the range of tan−1 x.
उत्तर
The range of
\[\tan^{- 1} x\] is
\[\left( - \frac{\pi}{2}, \frac{\pi}{2} \right)\]
APPEARS IN
संबंधित प्रश्न
If a line makes angles 90° and 60° respectively with the positive directions of x and y axes, find the angle which it makes with the positive direction of z-axis.
Find the principal values of the following:
`cos^-1(sin (4pi)/3)`
Evaluate the following:
`cos^-1(cos12)`
Evaluate the following:
`tan^-1(tan (6pi)/7)`
Evaluate the following:
`sec^-1(sec (2pi)/3)`
Evaluate the following:
`sec^-1(sec (25pi)/6)`
Evaluate the following:
`cot^-1(cot (19pi)/6)`
Evaluate the following:
`cot^-1{cot ((21pi)/4)}`
Write the following in the simplest form:
`cot^-1 a/sqrt(x^2-a^2),| x | > a`
Evaluate:
`cot{sec^-1(-13/5)}`
Evaluate:
`cos(tan^-1 3/4)`
Evaluate:
`sin(tan^-1x+tan^-1 1/x)` for x < 0
Evaluate:
`cot(tan^-1a+cot^-1a)`
`sin(sin^-1 1/5+cos^-1x)=1`
`sin^-1x=pi/6+cos^-1x`
Find the value of `tan^-1 (x/y)-tan^-1((x-y)/(x+y))`
`sin^-1 63/65=sin^-1 5/13+cos^-1 3/5`
`(9pi)/8-9/4sin^-1 1/3=9/4sin^-1 (2sqrt2)/3`
Evaluate the following:
`tan{2tan^-1 1/5-pi/4}`
`2tan^-1 1/5+tan^-1 1/8=tan^-1 4/7`
Solve the following equation for x:
`tan^-1 1/4+2tan^-1 1/5+tan^-1 1/6+tan^-1 1/x=pi/4`
Solve the following equation for x:
`2tan^-1(sinx)=tan^-1(2sinx),x!=pi/2`
Prove that `2tan^-1(sqrt((a-b)/(a+b))tan theta/2)=cos^-1((a costheta+b)/(a+b costheta))`
Write the value of `sin^-1((-sqrt3)/2)+cos^-1((-1)/2)`
Write the value of cos−1 \[\left( \tan\frac{3\pi}{4} \right)\]
Write the value of cos \[\left( 2 \sin^{- 1} \frac{1}{2} \right)\]
Write the value of cos−1 (cos 6).
Write the value ofWrite the value of \[2 \sin^{- 1} \frac{1}{2} + \cos^{- 1} \left( - \frac{1}{2} \right)\]
Write the value of cos−1 \[\left( \cos\frac{5\pi}{4} \right)\]
What is the principal value of `sin^-1(-sqrt3/2)?`
Write the value of \[\tan^{- 1} \left( \frac{1}{x} \right)\] for x < 0 in terms of `cot^-1x`
If α = \[\tan^{- 1} \left( \tan\frac{5\pi}{4} \right) \text{ and }\beta = \tan^{- 1} \left( - \tan\frac{2\pi}{3} \right)\] , then
If \[\cos^{- 1} \frac{x}{2} + \cos^{- 1} \frac{y}{3} = \theta,\] then 9x2 − 12xy cos θ + 4y2 is equal to
If tan−1 3 + tan−1 x = tan−1 8, then x =
The value of \[\sin^{- 1} \left( \cos\frac{33\pi}{5} \right)\] is
The value of \[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right)\]
If x = a (2θ – sin 2θ) and y = a (1 – cos 2θ), find \[\frac{dy}{dx}\] When \[\theta = \frac{\pi}{3}\] .
Find the value of x, if tan `[sec^(-1) (1/x) ] = sin ( tan^(-1) 2) , x > 0 `.
The value of tan `("cos"^-1 4/5 + "tan"^-1 2/3) =`
