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प्रश्न
\[\int\frac{e^x}{1 + e^{2x}} dx\]
बेरीज
उत्तर
\[\int\frac{e^x dx}{1 + e^{2x}}\]
\[\text{let }e^x = t\]
\[ \Rightarrow e^x dx = dt\]
\[Now, \int\frac{e^x dx}{1 + e^{2x}}\]
\[ = \int\frac{dt}{1 + t^2}\]
\[ = \tan^{- 1} \left( t \right) + C\]
\[ = \tan^{- 1} \left( e^x \right) + C\]
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