Advertisements
Advertisements
प्रश्न
उत्तर
\[\int \left( \tan x + \cot x \right)^2 \]
\[ = \int\left( \tan^2 x + \cot^2 x + 2 \tan x \cot x \right)dx\]
\[ = \int\left( \tan^2 x + \cot^2 x + 2 \right)dx\]
\[ = \int\left[ \left( \sec^2 x - 1 \right) + \left( {cosec}^2 x - 1 \right) + 2 \right]dx\]
\[ = \int\left( \sec^2 x + {cosec}^2 x \right) dx\]
\[ = \tan x - \cot x + C\]
APPEARS IN
संबंधित प्रश्न
\[\int \tan^2 \left( 2x - 3 \right) dx\]
` ∫ sin x \sqrt (1-cos 2x) dx `
If \[\int\frac{2^{1/x}}{x^2} dx = k 2^{1/x} + C,\] then k is equal to
The primitive of the function \[f\left( x \right) = \left( 1 - \frac{1}{x^2} \right) a^{x + \frac{1}{x}} , a > 0\text{ is}\]
\[\int\text{ cos x cos 2x cos 3x dx}\]
\[\int \sec^4 x\ dx\]
\[\int {cosec}^4 2x\ dx\]
\[\int\frac{1 + \sin x}{\sin x \left( 1 + \cos x \right)} \text{ dx }\]
