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प्रश्न
\[\int \tan^2 \left( 2x - 3 \right) dx\]
बेरीज
उत्तर
\[\int \tan^2 \left( 2x - 3 \right)dx\]
\[ = \int\left[ \sec^2 \left( 2x - 3 \right) - 1 \right]dx\]
\[ = \int \sec^2 \left( 2x - 3 \right)dx - \int1dx\]
\[ = \frac{\text{tan } \left( 2x - 3 \right)}{2} - x + C\]
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