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If A =30o, then prove that : cos 2A = cos2A - sin2A = 1 – tan 2 A 1 + tan 2 A - Mathematics

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Question

If A =30o, then prove that :
cos 2A = cos2A - sin2A = `(1 – tan^2"A")/(1+ tan^2"A")`

Sum

Solution

Given A = 30°

cos2A = cos 2 (30°) = cos 60° = `(1)/(2)`

= `(3)/(4) – (1)/(4)`

= `(1)/(2)`

`(1 –  tan^2"A")/(1 + tan^2"A") = (1 – tan^2 30°)/(1 + tan^2 30°)`

= `(1 – (1)/(3))/(1+(1)/(3)`

= `(2)/(4)`

= '(1)/(2)`

∴ cos 2A = `cos^"A" – sin^2"A" = (1 – tan^2"A")/(1 + tan^2"A")`

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Chapter 23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios] - Exercise 23 (B) [Page 293]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (B) | Q 2.2 | Page 293

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