हिंदी

Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t. x : cosec (log x)[1 – cot (log x)] 

योग

उत्तर

Let I = `int "cosec" (log x)[1 - cot (log x)].dx`
Put log x = t
∴ et
∴ dx = et .dt

∴ I = `int "cosec" t (1 - cot t).e^t dt`

= `int e^t ["cosec"  t - "cosec"  t cot t].dt`

= `int e^t ["cosec"  t + d/dt ("cosec"  t)].dt`

= `e^t "cosec" t + c     ...[∵ int e^t [f(t) + f'(t)].dt = e^t f(t) + c]`

= x . cosec (log x) + c.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.3 [पृष्ठ १३८]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.3 | Q 3.9 | पृष्ठ १३८

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

If `int_(-pi/2)^(pi/2)sin^4x/(sin^4x+cos^4x)dx`, then the value of I is:

(A) 0

(B) π

(C) π/2

(D) π/4


Integrate the function in x sin 3x.


Integrate the function in x log x.


Integrate the function in x log 2x.


Integrate the function in tan-1 x.


Integrate the function in `((x- 3)e^x)/(x - 1)^3`.


Prove that:

`int sqrt(x^2 + a^2)dx = x/2 sqrt(x^2 + a^2) + a^2/2 log |x + sqrt(x^2 + a^2)| + c`


Find : 

`∫(log x)^2 dx`


Evaluate the following : `int x^3.tan^-1x.dx`


Evaluate the following : `int x.sin^2x.dx`


Evaluate the following : `int e^(2x).cos 3x.dx`


Evaluate the following: `int x.sin^-1 x.dx`


Evaluate the following : `int(sin(logx)^2)/x.log.x.dx`


Integrate the following functions w.r.t.x:

`e^-x cos2x`


Integrate the following functions w.r.t. x : `x^2 .sqrt(a^2 - x^6)`


Integrate the following functions w.r.t. x : `sec^2x.sqrt(tan^2x + tan x - 7)`


Integrate the following functions w.r.t. x : `sqrt(x^2 + 2x + 5)`


Integrate the following functions w.r.t. x : `sqrt(2x^2 + 3x + 4)`


Integrate the following functions w.r.t.x:

`e^(5x).[(5x.logx + 1)/x]`


Choose the correct options from the given alternatives :

`int (log (3x))/(xlog (9x))*dx` =


Choose the correct options from the given alternatives :

`int (sin^m x)/(cos^(m+2)x)*dx` = 


Choose the correct options from the given alternatives :

`int tan(sin^-1 x)*dx` =


Choose the correct options from the given alternatives :

`int (x- sinx)/(1 - cosx)*dx` =


Integrate the following with respect to the respective variable : `(sin^6θ + cos^6θ)/(sin^2θ*cos^2θ)`


Integrate the following w.r.t.x : cot–1 (1 – x + x2)


Integrate the following w.r.t.x : e2x sin x cos x


Choose the correct alternative from the following.

`int (1 - "x")^(-2) "dx"` = 


Evaluate: `int e^x/sqrt(e^(2x) + 4e^x + 13)` dx


Evaluate: `int "dx"/(25"x" - "x"(log "x")^2)`


`int (sin(x - "a"))/(cos (x + "b"))  "d"x`


`int ["cosec"(logx)][1 - cot(logx)]  "d"x`


`int (cos2x)/(sin^2x cos^2x)  "d"x`


State whether the following statement is True or False:

If `int((x - 1)"d"x)/((x + 1)(x - 2))` = A log|x + 1|  + B log|x – 2|, then A + B = 1


Evaluate `int 1/(x log x)  "d"x`


`int_0^"a" sqrt("x"/("a" - "x")) "dx"` = ____________.


`int cot "x".log [log (sin "x")] "dx"` = ____________.


Find `int_0^1 x(tan^-1x)  "d"x`


`int tan^-1 sqrt(x)  "d"x` is equal to ______.


`int x/((x + 2)(x + 3)) dx` = ______ + `int 3/(x + 3) dx`


Find: `int e^x.sin2xdx`


Find the general solution of the differential equation: `e^((dy)/(dx)) = x^2`.


If `π/2` < x < π, then `intxsqrt((1 + cos2x)/2)dx` = ______.


`int e^x [(2 + sin 2x)/(1 + cos 2x)]dx` = ______.


`int_0^1 x tan^-1 x  dx` = ______.


If `int (f(x))/(log(sin x))dx` = log[log sin x] + c, then f(x) is equal to ______.


Find `int e^x ((1 - sinx)/(1 - cosx))dx`.


`int1/(x+sqrt(x))  dx` = ______


`inte^(xloga).e^x dx` is ______


`int(xe^x)/((1+x)^2)  dx` = ______


Solve the following

`int_0^1 e^(x^2) x^3 dx`


Evaluate:

`intcos^-1(sqrt(x))dx`


Evaluate:

`int((1 + sinx)/(1 + cosx))e^x dx`


Evaluate:

`inte^x sinx  dx`


Evaluate:

`int (logx)^2 dx`


Evaluate `int tan^-1x  dx`


Evaluate:

`int (sin(x - a))/(sin(x + a))dx`


If u and v are two differentiable functions of x, then prove that `intu*v*dx = u*intv  dx - int(d/dx u)(intv  dx)dx`. Hence evaluate: `intx cos x  dx`


Complete the following activity:

`int_0^2 dx/(4 + x - x^2) `

= `int_0^2 dx/(-x^2 + square + square)`

= `int_0^2 dx/(-x^2 + x + 1/4 - square + 4)`

= `int_0^2 dx/ ((x- 1/2)^2 - (square)^2)`

= `1/sqrt17 log((20 + 4sqrt17)/(20 - 4sqrt17))`


Evaluate the following.

`intx^3 e^(x^2) dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)  dx`


Evaluate `int (1 + x + x^2/(2!))dx`


Evaluate the following.

`intx^2e^(4x)dx`


The value of `inta^x.e^x dx` equals


Evaluate:

`inte^x "cosec"  x(1 - cot x)dx`


Evaluate `int(1 + x + x^2/(2!))dx`.


Evaluate the following.

`intx^3/(sqrt(1 + x^4))dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×